Quote:
Originally Posted by Indigo
The second question is
and so the two equations becomes
n = dxq1 + 24
2n = dxq2 + 11
How do you solve them to get 37
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LIke this....
Assume original number= a
The divisor= d
The quotient of the division = x
So, a/d = x & the remainder= dx+24
Twice original no. divided by d, 2a divided by d & as a=dx+24, so
2a= 2dx+48. From the question this gives remainder of 11
2dx is divisible by d, so no remainder from this part
Hence, the remainder 11 should have come from 48/ d
& 48/ 37 gives a remainder of 11. So the divisor is 37.